Question

The value of tan 130 tan 140° + cos100° root1+tan100° + tan63° - tan 3°-root3 tan 63ºtan 3°is equal to
1
(A) 1
(B) root3
(C) 1/root3
(D) 2 + root3​

Answer 1

Answer:

2 hours ago · The value of tan 130 tan 140° + cos100° root1+tan100° + tan63° - tan 3°- root3 tan 63ºtan 3°is equal to1(A) 1(B… Get the ...

Answer 2

Answer:

ANSWER

tan(270)=tan(130+140)

⇒tan(180+90)=

1−tan(130).tan(140)

tan(130)+tan(140)

⇒

0

1

=

1−tan(130).tan(140)

tan(130)+tan(140)

⇒1−tan(130).tan(140)=0

⇒tan(130).tan(140)=1