Question

the value of tan^3 theta -1 / tan theta​

Answer 1

Step-by-step explanation:

$\frac{ \tan^{3}\alpha - 1}{ \tan\alpha } \\ = \frac{ \tan^{3} \alpha }{ \tan \alpha } - \frac{1}{ \tan \alpha } \\ = { \tan }^{2} \alpha - \cot\alpha$