Question

The value of tan 3A – tan 2A – tan A is equal to

Answer 1

Answer:

❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ:

⇒ tan 3A = tan (A + 2A)

⇒ tan 3 A = tanA + tan2A/ 1 – tan A . tan 2A

⇒ tan A + tan 2A = tan 3A – tan 3A. tan 2A . tan A

⇒ tan 3 A – tan 2A – tan A = tan 3A . tan 2A . tan A

$\sf\blue{hope \: this \: helps \: you!! \: }$

Answer 2

$\large{➩}$

Next, by cross multiplication,

⇒tan⁡3A(1−tan⁡Atan⁡2A)=tan⁡A+tan⁡2A

Next, by multiplying with tan 3A we get,

to the left side it becomes

to the right side we get

tan⁡3Atan⁡Atan⁡2A

⇒tan⁡3A−tan⁡2A−tan⁡A=tan⁡3Atan⁡Atan⁡2A

Hence, we can say that the value of

tan⁡3A−tan⁡2A−tan⁡A=tan⁡3Atan⁡2Atan⁡A