Question

The value of ( tan 45degree + cot 45degree ) + ( sec 45degree × cosec 45degree )

Answer 1

Answer:

4

Step-by-step explanation:

we know that cot(90-θ)=tanθ;cosec(90-θ)=secθ

Now (tan 45° + cot 45°)+(sec 45°×cosec 45°)

=[tan 45° + cot (90°-45°)]+(sec 45°×cosec (90°-45°)

=(tan 45° + tan 45°)+(sec 45° × sec 45°)

=2 tan 45° + $sec^{2}$45°

2(1)+$(\sqrt{2} )^{2}$

=2+2=4