Question

the value of tan theta from the equation 3(sec2theta-1) + 16 tan theta + 5=0 are.....​

Answer 1

Answer:

3(sec

2

θ+tan

2

θ)=5⇒tan

2

θ+1+tan

2

θ=

3

5

⇒2tan

2

θ+1=

3

5

⇒tan

2

θ=

3

1

=(

3

1

)

2

=(tan

6

π

)

2

⇒tanθ=±tan

6

π

⇒θ=nπ±

6

π