Question

the value of tan theta = underroot2 -1 , then the value of tan theta / 1+tan^2theta is

Answer 1

Answer:

A

nπ+

4

π

,nπ+

3

π

where nϵI

tan

2

θ−tanθ−

3

tanθ+

3

=0

⇒tanθ[tanθ−1]−

3

[tanθ−1]=0

⇒(tanθ−1)(tanθ−

3

)=0

⇒tanθ=1,tanθ=

3

So, the general solution is given by

θ=mπ+

4

π

,m∈I,θ=nπ+

3

π

,n∈I

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Answer 2

Answer:

$\frac{ \tan( a ) }{1 + { \tan( a) }^{2} } = \frac{ \sqrt{2} }{4}$

Step-by-step explanation:

for convenience Assuming theta = A

the step by step explanation is in the above figure