Question

the value of tan24.tan48.tan42.tan66.is​

Answer 1

Answer:

1

Step-by-step explanation:

Question :Tan 24. Tan 48. Tan 42. Tan 66

● As Tan (x) = Cot (90 -x),

■ We convet Tan 66 into Cot 24 and Tan 48 into Cot 42 .

■ Thus it became , tan 24 . Cot 24 . Tan 42. Cot 42

● As tan = 1 /cot

■ we convert cot 24 into 1/ tan 24 and cot 42 into 1/tan 42

■Thus it became , tan 24 . 1/tan24 . Tan 42 .1/tan 42

■ Multiplying Everything We get 1 as the answer

Answer 2

Answer:

tan24*tan48*tan42*tan66

tan24*cot(90-48)*tan42*cot(90-66)

tan24*cot42*tan42*cot24

so we know cot=1/tan

This implies that

tan24*(1/tan42)*tan42*(1/tan24). [1/tan=cot]

let's reaarange the obtained terms properly

tan24*(1/tan24)*tan42*(1/tan42)

So (tan24/tan24)*(tan42/tan42)

tan24/tan24= 1. &. tan42/tan42=1

This implies 1*1=1

Therefore final ans is 1