The value of tand, if sinA = 1 and LA lies is
second quadrant is
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Answer:
Given sinθ=1+t22t
Since, θ lies in the second quadrant
∴ cosθ<0
⇒cosθ=−1−sin2θ
=−1−(1+t2)24t2
=−(1+t2)2(1−t2)2
=−1+t2∣∣∣1−t2∣∣∣
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