Question

the value of tanx-cotx=2.​

Answer 1

$\frac{ \sin( \alpha ) }{ \cos( \alpha ) } + \frac{ \cos( \alpha ) }{ \sin( \alpha ) } = 2 \\ \frac{ { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} }{ \sin( \alpha ) \cos( \alpha ) } = 2 \\ \frac{1}{ \sin( \alpha ) \cos( \alpha ) } = 2 \\ 1 = 2 \sin( \alpha ) \cos( \alpha ) \\ i.e. \: \\ 1 = \sin(2 \alpha ) \\ therefore \: \alpha = 0$

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Answer 2

(sinx/cosx)-(cosx/sinx)=2
(sin²x+cos²x)/sinxcosx=2
1/sinxcosx=2
1=2sinxcosx
sin90=sin(2x)
therefore
2x=90
•x=45•

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