Question

The value of $(1+i)^{2n}+(1-i)^{2n}\:\&\:(n\:\in\:N)$ is zero if-

(a) n is odd

(b) n is multiple of 4

(c) n is even

(d) $\frac{n}{2}$ is odd​

Answer 1

Answer:

Step-by-step explanation:

Complex numbers:-

Given an equation,in which we have to find the nature of n.

Taking square of terms in bracket,we get an expression.

(2i)^n+(-2i)^n=0

Since,i^n can't be 0

Hence,we find 2^n+(-2)^n=0, satisfying only for odd values of n(1,3,5,...)

So, option A is correct.

Answer 2

Answer:

happy

Step-by-step explanation:

mark as a brainlist answer.