Question

The value of
$({27}^{ \frac{1}{3} } + {64}^{ \frac{1}{3} } )$
​

Answer 1

Answer:

$({27}^{ \frac{1}{3} } + {64}^{ \frac{1}{3} } ) \: = ( {3}^{3} )^{ \frac{1}{3} } + ( {4}^{3} )^{ \frac{1}{3} } \\ = ( {3} )^{3 \times \frac{1}{3} } + ( {4} )^{3 \times \frac{1}{3} } \\ = 3 + 4 \\ = 7 \\ thus \\ ({27}^{ \frac{1}{3} } + {64}^{ \frac{1}{3} } ) = 7$