Question

the value of
$4 \div {32}^{1 \div 5}$
​

Answer 1

Step-by-step explanation:

Answer:

The solution is (x, y) = (- 13, 46)

Step-by-step explanation:

Substitution Method :-

Solve one of the equations for either x = or y = .

Substitute the solution from step 1 into the other equation.

Solve this new equation.

Solve for the second variable.

Step 1: Solve one of the equations for either x = or y = .

Given equations are 3x+2y=53 and 2x+3y=47

3x+2y=53 ................................................. ( 1 )

2x+3y=47 ..................................................( 2 )

Step 1: Solve one of the equations for either x = or y = . We will solve first equation for y.

3x + 2y = 53

subtract 3x from the sides of above equation,

2y = 53 - 3x

y = \frac{53 - 3x}{2}

2

53−3x

Step 2: Substitute the solution from step 1 into the second equation.

Put value of y in equation (2),

2x + 3y = 47

2x + 3 (\frac{53 - 3x}{2}

2

53−3x

) = 47

2x + (\frac{159 - 9x}{2}

2

159−9x

) = 47

Step 3: Solve this new equation.

Multiply by 2 on both the sides in above equation,

4x + 159 - 9x = 94

159 - 5x = 94

subtract by 159 on both the sides in above equation,

159 - 5x -159 = 94 - 159

- 5x = 65

divide both the sides by -5 in above equation,

x = - 13

Step 4: Solve for the second variable

Put x = - 13 in y = \frac{53 - 3x}{2}

2

53−3x

y\,=\,\frac{53 + 39}{2}y=

2

53+39

y\,=\,\frac{92}{2}y=

2

92

y\,=\,46y=46

The solution is: (x, y) = (- 13, 46)

Answer 2

Answer:

2

Hope it might help you...

Thank you