Question

The value of
$f (4 sin x- 2/x) dx is (-N cos x - P In x+c)$
Then the value of N+P is​

Answer 1

Step-by-step explanation:

We have,

$\int \bigg(4 \sin(x) - \frac{2}{x} \bigg)dx = -N \cos(x) - P \ln(x) + C$

$\implies 4\int \sin(x) dx \: -2 \int \frac{1}{x} \: dx = -N \cos(x) - P \ln(x) + C$

$\implies - 4\cos(x) -2 \ln(x) + C = -N \cos(x) - P \ln(x) +C$

On comparing, we get, $N=4\:\:\:and\:\:\:P=2$

so,

N+P=6