Question

the value of
$f \frac{ logx {}^{2} }{x} dx$

​

Answer 1

Answer: $(logx^{2})^{2} /4$

Step-by-step explanation:

$I = \int\limits {[(logx^{2})/x ]} \, dx$

Let $logx^{2} = t$ and differentiate both sides

$(1/x^{2})2xdx = dt\\ (2/x)dx = dt\\dx/x = dt/2$

So, I = $\int\limits {t/2} \, dt = t^{2} /4$........(1)

Now, put the value of t in (1)

So, I = $(logx^{2})^{2} /4$

(I hope it will be marked as Brainliest)