Math, asked by vidushimakraria, 8 months ago

the value of
 \frac{1}{log_{4}(120) }  + \frac{1}{log_{5}(120)}  +  \frac{1}{log_{6}(120)}  =
a) 0

b) 1

c) 24

d) 120​

Answers

Answered by palytoxin
2

option b) 1 is the answer . see the image for detailed explanation

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