Question

the value of $sin^2 \dfrac{3\pi }{4}+ sec^2 \dfrac{5\pi}{3 } + tan^2 \dfrac{2\pi}{3}=$​

Answer 1

$sin \frac{3\pi}{4} = \frac{1}{ \sqrt{2} }$

$sec \frac{5\pi}{3} = 2$

$tan \frac{2\pi}{3} = \sqrt{3}$

$= > ( { \frac{1}{ \sqrt{2} } })^{2} + {2}^{2} + { \sqrt{3} }^{2} = \frac{1}{2} + 4 + 3 \\ = > \frac{1}{2} + 7 = \frac{15}{2}$

Answer 2

$\huge\underline\bold{AnSwEr,}$

$sin \frac{3\pi}{4} = \frac{1}{ \sqrt{2} }$

$sec \frac{5\pi}{3} = 2$

$tan \frac{2\pi}{3} = \sqrt{3}$

$= > ( { \frac{1}{ \sqrt{2} } })^{2} + {2}^{2} + { \sqrt{3} }^{2} = \frac{1}{2} + 4 + 3 \\ = > \frac{1}{2} + 7 = \frac{15}{2}$

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