Question

the value of
$\sqrt{248 + \sqrt{} 52 + \sqrt{144} }$
​

Answer 1

Answer:

$roots \: are \: canceled \: by \: root \: \sqrt{248 + \sqrt{144} + \sqrt{52} } = > \sqrt{248} + 144 + 52 = > \sqrt{248} + 196.on \: lining \: the \: root \: on \: \sqrt{248} + 196 \: is \: = > \sqrt{ \sqrt{248} + 196} = > 248 + \sqrt{196} = > 248 + 14 = > 262.$

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Answer 2

Answer:

16

Step-by-step explanation:

√(248+√52+√144)= √(248 + √(52+12))= √(248+√64)= √(248+8)=√256= 16