Question

The value of
$\sqrt[3]{1 + \sqrt{2} } \times \sqrt[6]{3 - 2 \sqrt{2} }$
is equal to

$2 - \sqrt{2}$
$\sqrt{2 } - 1$
$3 - 2 \sqrt{2}$
$1$
​

Answer 1

Answer:1

Step-by-step explanation:

First take the cube we get

(1 +√2)(√(3-2√2) )

Then square it, we get

=(1+2√2)² (3-2√2)

=(3+2√2)(3-2√2)

Apply a²- b² identity we get

= (3)²-(2√2)²

=9-8

=1