Question

the value of

$\sqrt{6 + \sqrt{6 + \sqrt{6 + ...........} } }$
​

Answer 1

Step-by-step explanation:

let it be equal to x

$x = \sqrt{6 + \sqrt{6 + \sqrt{6......} } }$

$x = \sqrt{6 + x}$

squaring on both sides

x^2=6+x

x^2-x-6=0

the values of x are 3,-2

as it can be -2

$\sqrt{6 + \sqrt{6 + \sqrt{6.........} } } = 3$

hope this helps u