The value of
sigma¹³i=1(i^n +i^n-1 is. (1) 1+ i (2) i (3) 1 (4)
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Answer:
(1+i)(1+i2)(1+i3)(1+i4)
we know i2=−1
i3=−i
and i4=1
then
(1+i)(1−1)(1−i)(1+1)
⇒(1+i)(0)(1−i)(2)
=0
Thanks
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