the value of the 3rd term of the expression 4n+1
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Tn =4n+1
sum =∑ 15/ k=1 (4k+1)
=∑
k=1
15
4k+∑
k=1
15
(1)
=4[1+2+3+4+..........+15]
=4×
2
15×(15+1)
+15
=480+15
=
495
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