Math, asked by babusurendra133k, 3 days ago

The value of the determine : Δ=∣∣∣∣1!2*2!3!2!3*3!4!3!4*4!5!∣∣∣∣ is​

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Answered by advyetas
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Δ=1[(6)(120)−(24)(24)]−2[(2)(120)−(6)(24)]+6[(2)(24)−(6)(6)]

Δ=1[720−576]−2[240−144]+6[48−36]

Δ=1(144)−2(96)+6(12)

Δ=144−192+72

Δ=24

Δ=4!

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