Question

the value of the discriminat of the equation x²+5x+5=0 is​

Answer 1

Answer:

-5+√5/2,-5-√5/2

Step-by-step explanation:

x²+5x+5=0

a=1 b=5 c=5

discriminator

b²-4ac

5²-4*1*5=25-20=5

some b²-4ac>0

roots are real

x=-5+-√[5²-4*1*5]/2*1

=-5+-√[25-20]/2

=-5+-√[5/2]

I think it is helpful for you

Answer 2

${\huge{\boxed{\underline{\textsf{\textbf{\color{pink}{Final\:An}{\pink{sw}{\purple{er:-}}}}}}}}}$

$\boxed{Discriminant \ is \ 5}$

$\huge\underbrace\red{\dag Given:- \dag}$

$x^{2}+5x+5=0$

$\huge\underbrace\pink {\dag To Find:- \dag}$

The discriminant  

$\huge\underbrace\green {\dag Formula\:Used:- \dag}$

$Discriminant = b^{2}-4as$  

$\huge\underbrace\green {\dag some \ things \ to \ know :-\dag}$

Here,

• $a=coefficient \ of \ x^{2} \implies {1}$

• $b=coefficient \ of \ x \implies{5}$

• $c=constant \ term \implies{5}$

$\huge\underbrace\purple{\dag Solution:- \dag}$

General form of the equation is ax^{x}+bx+c

Let’s put values in the equation  

We get

$Discriminant = b^{2}-4as$  

$D=25-4 \times 1 \times 5$ [←putted values in equation]

$D=25-4 \times 5$

$D=25-20$

$D=5$

Hence discriminant of equation $x^{2}+5x+5 \ is \ \boxed{5}$

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