Math, asked by gauripatil090394, 5 months ago

The value of the expression [2 cos^2 theta +2/1+cot^2 theta] is

Answers

Answered by manvi541

0

Step-by-step explanation:

2cos^2theta+2/1+cot^2theta

2cos^2 theta +2/cosec^2 theta

(cot^2A+cosec^2A=1)

2cos^theta + 2sin^2 theta

(1/cosecA=sinA)

2(cos^theta +sin^2 theta)

=2

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