Question

The value of the given real number is equal to (root 32+ root 48)÷(root 8 + root 12)​

Answer 1

Answer:

geyebveiwoow shisi hsowpw dhudje eiwow heieoeoe urriiiyr iepwow ryurpe euueow euieoeo thutirireo hfipw feiowiwi rio hrrueurtehwbowei @52@'

Answer 2

Step-by-step explanation:

$\bf \underline{Solution-}$

$\textsf{Given}$

$\sf{ \frac{ \sqrt{32} + \sqrt{48} }{ \sqrt{8} + \sqrt{12} } }$

$\sf{ = \frac{ \sqrt{16 \times 2} + \sqrt{16 \times 3} }{ \sqrt{4 \times 2} + \sqrt{4 \times 3} } }$

$\sf{ = \frac{4 \sqrt{2} + 4 \sqrt{3} }{2 \sqrt{2} + 2 \sqrt{3} } }$

$\sf{ = \frac{4 ( \sqrt{2 } + \sqrt{3}) }{2( \sqrt{2} + \sqrt{3} )} }$

$\sf{ = \frac{4}{2} }$

$\sf{ = 2 \:Ans. }$