Math, asked by khushig2602, 6 hours ago

The value of the integral, ∫[x^2 - 2x - 2] x ∈ [3, 1] dx, where [x] denotes the greatest integer less than or equal to x, is :  ​

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Answered by itsRakesh
0

Answer:

Convert x^2-2x-2 into (x-1)^2 - 3 and solve

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