Question

The value of the lim x--- - infinity ((4x^2-x) + 2x) is:

Answer 1

here this answer


limx→∞x2−42+x−4x2

by l'Hopital's Rule (∞/∞),

=limx→∞2x1−8x

by l'Hopital's Rule (∞/∞) again,

=limx→∞2−8=2−8=−14

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