The value of the limit lim(√4n +n-2n) is
a) 0
b)1/4
c) undefined
d) infinity
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1
Evaluate the following limit:
limn→∞(4n2+n−−−−−−√−2n)
So far I've come up with this: limn→∞(4n2+n−−−−−−√−2n) = limn→∞(4n2(1+14n−−−−−−−−−−√)−2n) = limn→∞(2n(1+14n−−−−−−−√)−2n) = limn→∞(2n((1+14n−−−−−−−√)−1)). I think it's pretty clear from here that this goes to infinity, but how can I justify that the 2n grows stronger to infinity than the part in the brackets goes to zero? I know standard rules about exponential functions growing harder than polynomials, but not about this.
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