Question

the value of the m in the following given figure is pls reply fast urgent!!! ​

Answer 1

Answer:

option c

Step-by-step explanation:

Angle CAB = m

Angle ACD = 136°

Angle ABC = 63°

BCD is a straight line

Angle ACB = 180°- Angle ACD

= 180° - 136°

= 44°

Now as we know sum of angles of a triangle is 180°

Angle ABC + Angle ACB + Angle CAB = 180°

63° + 44° + m = 180°

107° + m = 180°

m = 180° - 107°

m = 73° Ans

Answer 2

★ Solution :-

In this question, we're given with a diagram of a triangle which consists of an exterior angle and are also given with the values of the exterior angle and one of the interior angle. One of the angle on the triangle is marked by a letter m. We are asked to find the value of the angle m.

In the attachment provided, first we should find the value of x.

Value of x :-

$\sf \leadsto Straight \: line \: angle = {180}^{\circ}$

$\sf \dashrightarrow {136}^{\circ} + x = {180}^{\circ}$

$\sf \leadsto x = 180 - 136$

$\sf \leadsto x = {44}^{\circ}$

Now, we can find the value of m in the triangle given.

Value of m :-

$\sf \leadsto {Angle \: sum \: property}_{(Triangle)} = {180}^{\circ}$

$\sf \leadsto \angle{A} + \angle{B} + \angle{C} = {180}^{\circ}$

$\sf \leadsto m + {63}^{\circ} + {44}^{\circ} = {180}^{\circ}$

$\sf \leadsto m + {107}^{\circ} = {180}^{\circ}$

$\sf \leadsto m + 107 = 180$

$\sf \leadsto m = 180 - 107$

$\sf \leadsto m = {73}^{\circ}$

Therefore, the value of the ∠m is 73°.