The value of the machine depreciation at the rate of 10%annum. If its present value of 10000 what will be its value after 2 year
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Answered by
1
the rate of depreciation= i = 10%
no.of years for which the machine will be put to use =n= 2
value at the end of 2 years = A
P = value at the beginning = 10000
P(1-i)^n = A
10000(1-10/100)^2= A
10000(1- 0.1)^2 = A
10000(0.9)^2 = A
10000(0.81) = A
A = 8100
A= 8100= value of the machine after 2years
no.of years for which the machine will be put to use =n= 2
value at the end of 2 years = A
P = value at the beginning = 10000
P(1-i)^n = A
10000(1-10/100)^2= A
10000(1- 0.1)^2 = A
10000(0.9)^2 = A
10000(0.81) = A
A = 8100
A= 8100= value of the machine after 2years
Answered by
3
Greetings..!
Present value of car = Rs 10000
Annual Decrease =10%
Decrease in first year = 10% of 10000=(10/100)*10000=Rs 1000
Price at the end of first year = Rs 10000-1000=Rs 9000
Decrease in second year = 10 % = 10% of 9000 = (10/100)*9000=Rs 900
∴It's price after two years = Rs 9000-900=Rs 8100(answer)
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