Question

The value of the magnetic moment of a particular ion is 2.83 Bohr magneton. The ion is
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Answer 1

Answer:

$b = \sqrt{n({n + 2) }}$

n= no. of unpaired electons

n=4 is answer

Answer 2

Answer:

Explanation:

Magnetic moment of the ion = 2.83 Bohr magneton.

Calculation of spin only magnetic moment -

u = √{n(n+2)}

where u is the magnetic moment in (BM) and  n is the number of unpaired electron  

n = 1 --- 5 ( number of unpaired e`)

- wherein

V² → 3d³ = √ 3 ( 3+2)

= √15

= 3.87

= 3+.9 → 3.9(BM)

Magnetic movement u = √ x ( x+2)

= x(x + 2) = 8

= x = 2

Therefore, the value of ion is 2.