Question

the value of the polynomial 4n^+4+5n^3-n^2+8 at n=1 ?​

Answer 1

Answer:

a=−4n4−5n3+n2+1/8nt

Step-by-step explanation:

Let's solve for a.

4n4+5n3−n2+8atn=1

Step 1: Add -4n^4 to both sides.

4n4+8ant+5n3−n2+−4n4=1+−4n4

8ant+5n3−n2=−4n4+1

Step 2: Add -5n^3 to both sides.

8ant+5n3−n2+−5n3=−4n4+1+−5n3

8ant−n2=−4n4−5n3+1

Step 3: Add n^2 to both sides.

8ant−n2+n2=−4n4−5n3+1+n2

8ant=−4n4−5n3+n2+1

Step 4: Divide both sides by 8nt.

8ant/8nt=−4n4−5n3+n2+1/8nt

a=−4n4−5n3+n2+1/8nt

Answer:

a=−4n4−5n3+n2+1/8nt

Answer 2

Answer:

16....mark me as brainliest