Question

The value of the polynomial f(x) =6x^3 +4x^2-x/3 at x=1/3

Answer 1

Answer:

6x^3+4x^2-x/3 eill be 5/9

Step-by-step explanation:

6(1/3*1/3*1/3)+4(1/3*1/3)-(1/3/3)

6(1/27)+4(1/9)-1/9

6/27+4/9-1/9

2/9-+(4/9-1/9)

2/9+3/9

5/9

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Answer 2

The answer is $\frac{5}{9}$.

Given: f(x) = 6x³ + 4x² - $\frac{x}{3}$

           x = $\frac{1}{3}$

To find: the value of the polynomial at the given value of x.

Substituting the value of x in the polynomial,

f(x) = 6 × $(\frac{1}{3})^{3}$ + 4 ×$(\frac{1}{3} )^{2}$ - $\frac{1}{3} \times \frac{1}{3}$

     = $\frac{6}{27}$ + $\frac{4}{9}$ - $\frac{1}{9}$

L.C.M of 27 and 9 = 27

= $\frac{6 \times 1 +4 \times 3 - 1 \times 3 }{27}$

= $\frac{6 + 12 - 3}{27}$

= $\frac{18-3}{27}$

= $\frac{15}{27}$

= $\frac{5}{9}$

Answer: The value of the polynomial is $\frac{5}{9}$.

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