Question

the value of the polynomial f(x)=6x^3+4x^2-x/3 at x=1/3

Answer 1

f(x)=
$6 {x}^{3} + 4 {x}^{2} - \frac{x}{3}$
$= > f( \frac{1}{3} ) = 6( { \frac{1}{3} })^{3} + 4( { \frac{1}{3} })^{2} - \frac{ \frac{1}{3} }{3} \\ = > \frac{2}{9} + \frac{4}{9} - \frac{1}{9} \\ = > \frac{5}{9}$.

Answer 2

Hope it will help u if not understood plz ask