Math, asked by abbi26, 1 year ago

the value of the polynomial p(x)=x^2-2x+3 at x=-1 is​

Answers

Answered by anirudh8339
5

Answer:

let's find zero of polynomial first

x=-1 okk

let put value of x in the p(x)

p(-1) =-1^2-2(-1) +3

=1+2+3

6 is your answer buddy

Answered by karthikeyanmuthukuma
1

Answer:

The remainder is 6.

Step-by-step explanation:

Given,

x=1,

so substitute x as -1 in all the places.

Now, p(x)=x^2-2x+3

=-1^2-2(-1)+3

=1-(-2)+3

=1+2+3

=6.

Hope it is useful.

please mark me as the brainliest.

Similar questions