The value of the product of (x – a)(x – b)(x – c), given that the sum a + b + c =7, ab + bc + ca =0
and abc = - 36
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Step-by-step explanation:
Expansion of (x-a)(x-b)(x-c) gives:
x^3 -(a+b+c)x+(ab+bc+ca)-abc
Therefore, on substituting (a+b+c)=7, ab+bc+ac=0, and -abc=36, you get
x^3-7x^2+36=0
Hope you understood it :)
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