Question

The value of the reaction quotient, Q, for the cell; Ni(s)∣∣Ni2+(0.9M)∣∣∣∣Cl−(0.40M)∣∣Cl2(g,0.10atm),Pt(s) is

Answer 1

Answer : The value of the reaction quotient, Q, for the cell is, 1.44

Explanation:

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given cell reaction is :

$Ni(s)|Ni^{2+}(0.9M)||Cl^-(0.40M)|Cl_2(g)(0.10atm),Pt(s)$

The balanced two-half reactions will be,

Oxidation half reaction : $Ni(s)\rightarrow Ni^{2+}(aq)+2e^-$

Reduction half reaction : $Cl_2(g)+2e^-\rightarrow 2Cl^-(aq)$

Thus the overall reaction will be,

$Ni(s)+Cl_2(g)\rightarrow Ni^{2+}(aq)+Cl^-(aq)$

The expression for reaction quotient will be :

$Q=\frac{[Ni^{2+}(aq)][Cl^-(aq)]^2}{[Cl_2(g)]}$

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

$Q=\frac{(0.9M)\times (0.40M)^2}{(0.10atm)}=1.44$

Therefore, the value of the reaction quotient, Q, for the cell is, 1.44