Physics, asked by nomulashivani2, 11 months ago

The value of universal gravitation al constant in CGS system is 6.67×10^-8 dynecm^-2gm^-2.Its value in SI system is??
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Answers

Answered by NIKHILRAWAT64
1

Answer:

6.67 × 10^-8 dyne.cm²/g²

6.67 × 10^-8 dyne.cm²/g²we know ,

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m1 g = 10^-3 kg

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m1 g = 10^-3 kguse this here ,

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m1 g = 10^-3 kguse this here ,6.67 × 10^-8 × ( 10^-5) .(10^-2)²/(10^-3)²

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m1 g = 10^-3 kguse this here ,6.67 × 10^-8 × ( 10^-5) .(10^-2)²/(10^-3)²= 6.67 × 10^-8 { 10^-5× 10^-4 /10^-6} Nm²/kg²

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m1 g = 10^-3 kguse this here ,6.67 × 10^-8 × ( 10^-5) .(10^-2)²/(10^-3)²= 6.67 × 10^-8 { 10^-5× 10^-4 /10^-6} Nm²/kg²= 6.67 × 10^-8- × 10^-3 N.m²/kg²

6.67 × 10^-8 dyne.cm²/g²we know ,1 dyne = 10^-5 N1 cm = 10^-2 m1 g = 10^-3 kguse this here ,6.67 × 10^-8 × ( 10^-5) .(10^-2)²/(10^-3)²= 6.67 × 10^-8 { 10^-5× 10^-4 /10^-6} Nm²/kg²= 6.67 × 10^-8- × 10^-3 N.m²/kg²= 6.67× 10^-11 Nm²/kg²

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