Question

The value of V(64)
$\sqrt[3]{64} ^{ - 1}$
Pls bta dijiye bhaiya didi please​

Answer 1

Answer:

Hence $\frac{1}{4}$ is the required answer

Explanation:

We have to find the value of ,

⇒  $\sqrt[3]{64} ^{-1}$

⇒  $( 4)^{-1}$ [ As the cube root  of 64 is 4 ( 4x4x4 ) ]

⇒  $\frac{1}{4^1}$   [ As the 4 will go to the denominator the sign of the power will change]

⇒  $\frac{1}{4}$     [ As $4^{1}$ = 4 ]