The value of van't Hoff factors for KCl, NaCl and K₂SO₄
respectively are ............ .
(a) 2, 2 and 2 (b) 2, 2 and 3
(c) 1, 1 and 2 (d) 1, 1 and 1
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Answer:
The value of van't Hoff factors for KCl, NaCl and K₂SO₄
respectively are ............ .
a) 2, 2 and 2
(b) 2, 2 and 3
(c) 1, 1 and 2
(d) 1, 1 and 1
Answered by
0
The factors are 2, 2 and 3 respectively.
Option (B) is correct.
Explanation:
The compounds have the following ions when they are ionized.
- KCl (K+ + Cl-) ionize to give ions
- NaCl (Na+ + Cl-) ionize to give 2 ions
- K2SO4 (2K+ + SO4–) ionizes to give 3 ions.
Therefore van’t Hoff factors for KCl, NaCl and K2SO4 are 2, 2 and 3 respectively.
Thus the factors are 2, 2 and 3 respectively.
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