Chemistry, asked by jaleswat31431, 10 months ago

The value of van't Hoff factors for KCl, NaCl and K₂SO₄
respectively are ............ .
(a) 2, 2 and 2 (b) 2, 2 and 3
(c) 1, 1 and 2 (d) 1, 1 and 1

Answers

Answered by Anonymous
3

Answer:

The value of van't Hoff factors for KCl, NaCl and K₂SO₄

respectively are ............ .

a) 2, 2 and 2

(b) 2, 2 and 3

(c) 1, 1 and 2

(d) 1, 1 and 1

Answered by Fatimakincsem
0

The factors are 2, 2 and 3 respectively.

Option (B) is correct.

Explanation:

The compounds have the following ions when they are ionized.

  • KCl (K+ + Cl-) ionize to give ions
  • NaCl (Na+ + Cl-) ionize to give 2 ions
  • K2SO4 (2K+ + SO4–) ionizes to give 3 ions.

Therefore van’t Hoff factors for KCl, NaCl and K2SO4 are 2, 2 and 3 respectively.

Thus the factors are 2, 2 and 3 respectively.

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