The value of (x+1/x)^2 is k when x^2+1/x^2=27 find the ones digit of k
Answers
Answered by
1
Answer:
x−
x
1
We have,
(x−
x
1
)
2
=x
2
−2×x×
x
1
+
x
2
1
⇒(x−
x
1
)
2
=x
2
−2+
x
2
1
⇒(x−
x
1
)
2
=x
2
+
x
2
1
−2
⇒(x−
x
1
)
2
=27−2[∵x
2
+
x
2
1
=27 given]
⇒(x−
x
1
)
2
=25⇒(x−
x
1
)
2
⇒x−
x
1
=±5
[Taking square root of both sides]
Similar questions