Math, asked by Zuzu20, 3 months ago

The value of (x^2 - 9) - (x-3)(x+3)

Answers

Answered by pramolvats
1

Answer:

(x²-9)-(x-3)(x+3)

= (x²-9)-(x²-3x+3x-9)

=(x²-9)-(x²-9)

=0

Answered by AbdullahAsad496
1

Answer:

0

Step-by-step explanation:-

Input:

(x^2 - 9) - (x - 3) (x + 3)

Following the property (a+b)(a-b)= a^{2}-b^{2}:

=(x^2-9)-(x^2-9)

Result:

0

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