Question

the value of x^2x+x(x^x) when the value of x=2 is

Answer 1

Answer:

16

if you want step by step explanation then comment me

Answer 2

Given: The equation is$x^2x+x(x^x)$ and$x=2$.

We have to find the value of the above equation.

As we know that the value of$x$ is given, so by putting this value in the above equation we are solving the above equation.

We are solving in the following way:

We have,

$x^2x+x(x^x)$

$=>2^2\times2+2(2^2)\\=>4\times2+2(4)\\=>8+8\\=>16$

Hence, the value of the equation $x^2x+x(x^x)$is$16$.