the value of x^3 - y^3 % x^2 +xy + y^2
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Given that, a + b = 1
Taking cube of both sides, we get
(a + b)3 = 1
⇒ a3 + b3 + 3ab(a + b) = 1
⇒ a3 + b3 + 3ab = 1
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