Question

the value of (x-a)³+(x-b)³+(x-c)³-3(x-a)(x-b)(x-c) when a-b-c=3x please help me !!! to solve this question​

Answer 1

Answer:

Let x-a = p, x-b = q and x-c = r

The given expression becomes p^3+q^3+r^3 -3pqr = (p+q+r)(p^2+q^2+r^2-pq-qr-rp)……..(1)

Now p+q+r= x-a+x-b+x-c = 3x-(a+b+c)=3x-3x =0.

So, p+q+r =0. Hence (1) reduces to 0.

Or the given expression = 0.