the value of x^a-b/bc×x^c-a/ca×x^a-b/bc
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First, (b-c) x (c-a) is a vector, (a-b) also and then (a-b).((b-c) x (c-a)) is a scalar (b-c) x (c-a) = b x (c-a) - c x (c-a) = b x c - b x a -c x c - c x ...
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