the value of x : and explain please give answer fastly .
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Hey friend
Given-:
Angle CAB=30°
Angle ABC=45°
Angle CDM=20°
To find-:
Angle AMD(x)= ?
Solution--:
AngleCAB+AngleABC+AngleACB=180°
{Angle sum prop.)
30°+45°+AngleACB=180°
75°+Angle ACB=180°
Angle ACB= 105°
Now,
Angle ACB+AngleMCD=180° (linear pair)
105°+Angle MCD=180°
Angle MCD=75°
Now,
Angle MCD+Angle CDM= Angle X
( Exterior angle prop.)
75°+25°=Angle X
Angle X=95°
Be perfectionist
Given-:
Angle CAB=30°
Angle ABC=45°
Angle CDM=20°
To find-:
Angle AMD(x)= ?
Solution--:
AngleCAB+AngleABC+AngleACB=180°
{Angle sum prop.)
30°+45°+AngleACB=180°
75°+Angle ACB=180°
Angle ACB= 105°
Now,
Angle ACB+AngleMCD=180° (linear pair)
105°+Angle MCD=180°
Angle MCD=75°
Now,
Angle MCD+Angle CDM= Angle X
( Exterior angle prop.)
75°+25°=Angle X
Angle X=95°
Be perfectionist
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