Question

The value of x and y, if the given system of equations is √3x +2y = 0 , √5x+2√2y=0 are (a)x=0, y=1 (b)x=0, y=0 (c)x=1, y=1 (d)none of these

Answer 1

Answer:

(b) x = 0, y = 0

Step-by-step explanation:

√3x +  2y     =  0          → 1

√5x + 2√2y =  0          → 2

Multiplying eqn. 1 by √2,

√6x + 2√2y = 0       → 3

Now, solving eqn. 3 and 2:

    √6x  +  2√2y   = 0     → 3    [eqn. (3 - 2) ]

(-) √5x  + (-)2√2y =  0    → 2

  ----------------------------------

         √6x - √5x = 0

-----------------------------------

⇒   x(√6 - √5) = 0

∴    x = 0

Substituting x in y,

√3x + 2y = 0

√3(0) + 2y = 0

      0 + 2y = 0

             2y = 0

         ⇒   y = 0

Hence, the option is (b) x = 0, y = 0.