the value of x and y in x+y/xy=7 and 3x+2y/xy=17
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Given : (x + y)/xy = 7 , (3x + 2y)/xy = 17
x and y are not equal to zero
To Find : x and y
Solution:
(x + y)/xy = 7
=> x + y = 7xy Eq1
(3x + 2y)/xy = 17
=> 3x + 2y = 17xy Eq2
Eq2 - 2 * Eq1
=> x = 3xy
=> 1 = 3y
=> y = 1/3
Eq2 - 3 * Eq1
=> -y = -4xy
=> x = 1/4
x = 1/4 and y = 1/3
Learn More:
Solve the following x+y/xy=5 and x-5/xy=7
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