The value of x and y when a point lies on linear equation 2x-3y=12
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Answered by
2
Answer:
Hi friends
Step-by-step explanation:
when x = 0
→ 2 * 0 - 3y = 12
→ (-3y) = 12
→ y = (-4) .
when y = 0
→ 2x - 3 * 0 = 12
→ 2x = 12
→ x = 6
when x = 3
→ 2*3 - 3y = 12
→ 6 - 3y = 12
→ (-3y) = 12 - 6
→ (-3y) = 6
→ y = 6/(-3)
→ y = (-2)
so, three possible values of (x , y) are (0, - 4) , (6, 0) and (3, -2) .
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There will be infinite number of solutions .
Answered by
5
Answer:
Put x=6 and y=0 in given equation.
2x−3y=2×6−3×0
=12-0
=12
Hence, the value of x and y that satisfy the equation are (6,0).
Step-by-step explanation:
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